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45x^2-81x+36=0.
a = 45; b = -81; c = +36;
Δ = b2-4ac
Δ = -812-4·45·36
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{81}=9$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-81)-9}{2*45}=\frac{72}{90} =4/5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-81)+9}{2*45}=\frac{90}{90} =1 $
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